For a particular reaction, Δ𝐻=−328.21 kJ and Δ𝑆=98.7 J/K.

Question

Calculate  for this reaction at 298 K.

Δ𝐺=_______KJ

Answer 1

∆G = ∆H - T∆S

∆H = -328.21 kJ

∆S = 98.7 J/K = 0.0987 kJ/K (to keep units the same as ∆H)

∆G = -328.21 kJ - (298K)(0.0987 kJ/K)

∆G = -328.21 kJ - 29.41 kJ

∆G = -357.62 kJ