Alessia B.
asked • 04/12/22Solve 9 cos ( 2 ϕ ) = 9 sin 2 ( ϕ ) + 1 for all solutions 0 ≤ ϕ < 2 π
Solve 9cos(2ϕ)=9sin2(ϕ)+1 for all solutions 0≤ϕ<2π
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1 Expert Answer
Mark M. answered • 04/13/22
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Mathematics Teacher - NCLB Highly Qualified
9 cos (2Φ) = 9 sin2 Φ + 1
9 [1 - sin2 Φ] = 9 sin2Φ + 1
So much for the Trigonometry. Now use Algebra to solve for Φ
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Paul M.
04/12/22