The sum of two numbers is 44. One number is 2 more than twice the other. Write a system of equations that defines this situation and solve using any method.

Answer 1

X + Y = 44

Y = 2X + 2

This lends itself very easily to substitution

X + (2X + 2) = 44

X + 2X + 2 = 44

3X + 2 = 44

3X = 42

X = 14

Y = 2(14) + 2

Y = 28 + 2

Y = 30

Now we check by verifying that the 2 numbers do indeed add up to 44.