PLEASE HELP WITH CHEM LIMITING REACTANTS PLEASE

Question

Given the equation: SIO2 (s) + 4 HF (g) ---- SiF4 (g) + 2 H2O (I)

If we start with 6 moles of HF and 45 grams of Si02 which is the Mass of Sf02 is 60.09 grams/mol.

Answer 1

SIO₂ (s) + 4 HF (g) ---- SiF₄ (g) + 2 H₂O (I) ... balanced equation

If you are asking which reactant is limiting, there's an easy way to find this out.

Divide the moles of each reactant by the corresponding coefficient in the balanced equation. Whichever values comes out less is the limiting reactant.

For SiO₂ we have ... 45 g SiO₂ x 1 mol / 60.09 g = 0.749 mols SiO₂ (÷1->0.749)

For HF we have ... 6 mols HF (÷4->1.5)

Since 0.749 is less than 1.5, the limiting reactant is SiO₂ and there are 0749 moles of it.