J.R. S. answered 04/12/22
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = -RT ln K
∆Gº = -17.7 kJ
R = 8.314 J/Kmol = 0.008314 kJ/Kmol
T = 298K
-17.7 = -(0.008314)(298) ln K
-17.7 = -2.48 ln K
ln K = 7.14
K = 1261
Kelly B.
asked 04/12/22In glycolysis, the hydrolysis of ATP to ADP is used to drive the phosphorylation of glucose (GLC):
GLC + ATP <--> ADP + GLC -- 6 -- phosphate
∆G°= -17.7 kJ
What is the value of Kc for this reaction at 298 K?
J.R. S. answered 04/12/22
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = -RT ln K
∆Gº = -17.7 kJ
R = 8.314 J/Kmol = 0.008314 kJ/Kmol
T = 298K
-17.7 = -(0.008314)(298) ln K
-17.7 = -2.48 ln K
ln K = 7.14
K = 1261
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