What is the ΔG° of the reaction at 350 K in kJ/mol?

Question

An aqueous reaction at 350 K has an equilibrium constant (K_c) of 5.74 × 10^-2 .

What is the ΔG° of the reaction at 350 K?

______ kJ/mol

Answer 1

Not sure you can really refer to ∆Gº at 350K since ∆Gº is defined at 298K. This should properly read "what is the ∆G of the reaction at 350K"?

The best I can come up with with the above caveat in mind would be the following:

∆G = -RT lnK = -(8.314 J/Kmol)(350K) ln 5.74x10^-2

∆G = -2910 J/mol x -2.86

∆G = 8322 J/mol = 8.32 kJ/mol