How do i solve this problem?

Question

If csc0=5/4 and is located on the interval [pie,3pie/2], find sin 20. Find cos20. Find tan 20

Answer 1

The csc of am angle in the third quadrant is negative. Your question says is positive so something is wrong with that question.

Answer 2

csc0 = 5/4 = 1/sin0 = 1/1 =1 but 5/4 doesn't equal 1

there's a mistake in the problem. It has a contradiction.

UNLESS maybe you meant theta, not zero

let x = theta

then cscx = 5/4 = 1/sinx

then cross multiply

to get

5sinx = 4

sinx = 4/5 = .8

x = about 53.13 degrees

which seems totally irrelevant & contradictory to

sin20 =.342

cos20 = .94

tan20 = .364

as 20 is not in quadrant III, plus the theta of cos(theta) is also not in quadrant III.

there's a problem with the problem. A Number wrong here or there.