chemistry hw help

Question

At 1120 K, ∆G° = 53.9 kJ/mol for the reaction 3 A (g) + B (g) →2 C (g). If the partial pressures of A, B, and C are 11.5 atm, 8.60 atm, and 0.510 atm respectively, what is the free energy for this reaction?

Answer 1

∆G = ∆Gº + RT ln Q

Q = (C)² / (A)³⁽B) = (0.510)² / (11.5)³(8.60) = 0.2601 / 1.31x10⁴ = 1.99x10^-5

∆Gº = 53.9 kJ/mol

R = 0.008314 kJ/Kmol

T = 1120K

∆G = 53.9 + (0.008314)(1120) ln 1.99x10^-5

Solve for ∆G