J.R. S. answered 04/10/22
Ph.D. University Professor with 10+ years Tutoring Experience
Looking at the electron configuration for Sr we have ...
[Kr]5s2
So IE1 is to remove the first 5s electron ->[Kr]5s1
IE2 is to remove the 2nd 5s electron -> [Kr]
IE3 would be a big jump because you are trying to remove an electron from the noble gas configuration which is very stable. So, the answer would be IE3 would be the largest jump.