J.R. S. answered 04/09/22
Ph.D. University Professor with 10+ years Tutoring Experience
(A) In2(SO4)3(s) ==> 2 In3+(aq) + 3 SO42-(aq)
Ksp = [In3+]2[SO42-]3
[In3+] = 2 x 0.0048 M = 0.0096 M
[SO42-] = 3 x 0.0048 M = 0.0144 M
Ksp = (0.0096)2(0.0144)3
Ksp = 2.75x10-10
(B) Common ion effect:
[SO42-] = 0.200 M
Ksp = [In3+]2[SO42-]3 = (x)2(0.200)3
2.75x10-10 = 0.008x2
x = 1.85x10-4 M = [In3+]
molar solubility = 1/2 x 1.85x10-4 M = 9.25x10-5 M
(C) Common ion effect:
[SO42-] = 0.200 M= 0.150 M
Repeat above calculation is (B) but use 0.150 in place of 0.200 M for [SO42-]