J.R. S. answered 04/08/22
Ph.D. University Professor with 10+ years Tutoring Experience
A:
0.075 MHCl + H2O ==> 0.075 M H3O+ + 0.075 M Cl-
[OH-] = 1x10-14 / 0.075 = 1.33x10-13 M
B:
pH = -log [H3O+] = -log 0.075 = 1.12
C:
7.9x10-4 M HI + H2O ==> 7.9x10-4 M H3O+ + 7.9x10-4 M I-
[H3O+] = 7.9x10-4 M
[OH-] = 1x10-14 / 7.9x10-4 = 1.27x10-11 M
D:
pH = -log [H3O+] = -log 7.9x10-4 = 3.12