J.R. S. answered 04/07/22
Ph.D. University Professor with 10+ years Tutoring Experience
Volume of a spherical balloon with a diamter of 12 inches.
12 inches x 2.54 cm / inch = 30.48 cm
Volume of a sphere = 4/3 π r3 and r = 1/2 diamter = 1/2 x 30.48 cm = 15.24 cm
V = 4/3 x 3.14 x 3540 cm3
V = 14,819 cm3 = 14.8 L = initial volume of the balloon
Assuming the pressure remains constant, we can use the relationship between volume (V) and temperature (T), but T must be in Kelvin. ºF = ºC x 1.8 + 32 and ºC = ºF - 32 / 1.8
T1 = 72.0ºF = 22.2 C + 273 = 295.2K
T2 = 40.0 ºF = 4.44ºC + 273 = 277.4K
V1 = 14.8 L
V2 = ?
Volume and temperature relationship is V1/T1 = V2/T2
14.8 L / 295.2K = V2 / 277.4K
V2 = 13.9 L