use standardized normal value: z = (x - mean)/std = (x - 70)/2.5
top 15% is the 85th percentile.
for 85th percentile z = 1.04
so 1.04 = (x - 70)/2.5
x = 1.04 * 2.5 + 70 = 72.6
Andrea C.
asked 04/05/22If Air Force only accepts someone who is at top 15%, what is his minimum required height?
mean = 70 inches
standard deviation = 2.5 inches
use standardized normal value: z = (x - mean)/std = (x - 70)/2.5
top 15% is the 85th percentile.
for 85th percentile z = 1.04
so 1.04 = (x - 70)/2.5
x = 1.04 * 2.5 + 70 = 72.6
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.