J.R. S. answered 04/05/22
Ph.D. University Professor with 10+ years Tutoring Experience
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O ... balanced equation for titration
Volume of 0.241 M NaOH used = 41.45 ml - 0.20 ml = 41.25 ml = 0.04125 L
moles NaOH used = 0.04125 L x 0.241 mol/L = 0.00994 moles NaOH
moles H2SO4 present = 0.00994 mols NaOH x 1 mol H2SO4 / 2 mols NaOH = 0.00497 mols H2SO4
volume H2SO4 = 12.00 ml x 1 L / 1000 ml = 0.01200 L
Molarity of H2SO4 = 0.00497 mols / 0.01200 L = 0.414 M