Solve the following equations for x if 0 ≤ x ≤ 2𝜋

Question

4-4 tan(3x+1)=16

Answer 1

4- 4tan(3x+1) = 16

1-tan(3x+1) = 4

tan(3x+1) = -3

3x+1 = tan^-1(-3) = -71.57 or 288.43 or 108.43 = 288.43pi/180 or 108.43pi/180 = about 1.6pi or .6pi

3x = .6pi-1 or 1.6pi-1

x = .2pi-1/3 or .53pi- 1/3