J.R. S. answered 04/05/22
Ph.D. University Professor with 10+ years Tutoring Experience
Mole fraction KCl = moles KCl / (moles KCl + moles H2O)
molar mass KCl = 74.55 g / mol
molar mass H2O = 18.02 g / mol
Density of H2O @ 20ºC = 0.9982 g / ml
moles KCl present = 12.00 kg x 1000 g / kg x 1 mol / 74.55 g = 160.96 moles KCl
moles H2O present = 250.0 ml x 0.9982 g / ml x 1 mol / 18.02 g = 13.85 moles H2O
Total moles = 160.96 moles KCl + 13.85 moles H2O = 174.8 moles
Mole fraction KCl = 160.96 / 174.8 = 0.9208