Using the heat of fusion of water, 334 J/g , calculate the grams of ice that will melt at 0 ∘C if 1510 J is absorbed.

Answer 1

Since 0ºC is the freezing/melting point of water, melting the ice at 0º is simply a phase change without any change in temperature and the heat needed (q) = mass (m) x heat of fusion (∆H_f)

q = m∆H_f

1510 J = (m)(334 J/g)

m = 1510 J / 334 J/g)

m = 4.52 g of ice will melt