Find Sin 2A and Sin A/2

Question

If sec A=37 with 0° ≤ A ≤ 90°

Answer 1

secA= sqr37 = 1/cosA

cosA = 1/sqr37 = adjacent side/hypotenuse

sinA= opposite side/hypotenuse = sqr36/sqr37= 6/sqr37

sin2A = 2sinAcosA = 2(6/sqr37)(1/sqr37) = 12/37

sinA/2 = sqr((1-sinA)/2) = sqr((1-6/sqr37)/2)