Find z such that 64% of the standard normal curve lies between −z and z. (Round your answer to two decimal places.)

Answer 1

Since z and -z (same z opposite signs), that means we are dealing with a 64% region that is symmetric about the 50th percentile (z = 0), which would cover between the 50 - 32 = 18th and 50 + 32 = 82nd percentiles.

Look up the z-score for the 82nd percentile = 0.915