2 sinx - sqrt(2) - 0
sinx = sqrt(2)/2
sin is positive in 1st and 2nd quadrants and above is true when reference angle is 45 degrees
x = 45 and 135 degrees
Ashtin W.
asked • 04/02/22Find all solutions in the interval 0° ≤ 𝜃 < 360°. If rounding is necessary, round to the nearest tenth of a degree.
2 sin 𝜃 − 
2=0
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