Let sin A = − 5/13 with 270° ≤ A ≤ 360° and cos B = − 24/25 with 90° ≤ B ≤ 180° and find the following. sin(A + B)

Question

Let  sin A = −  5/13  with  270° ≤ A ≤ 360°  and  cos B = −  24/25  with  90° ≤ B ≤ 180°  and find the following. sin(A + B)

Yefim S. · Accepted Answer

sin(A + B) = sinAcosB + cosAsinB; cosA = √1 - 25/169 = 12/13; sinB = √1 - 576/625 = 7/25.sin(A + B) = - 5/13·(- 24/25) + 12/13·7/25 = 120/325 + 84/325 = 204/325

Let sin A = − 5/13 with 270° ≤ A ≤ 360° and cos B = − 24/25 with 90° ≤ B ≤ 180° and find the following. sin(A + B)

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Let sin A = − 5/13 with 270° ≤ A ≤ 360° and cos B = − 24/25 with 90° ≤ B ≤ 180° and find the following. sin(A + B)

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

tan^2x-sin^2x=tan^2xsin^2x

I need help trying to sole tan^2 x =1 where x is more than or equal to 0 but x is less than or equal to pi

find all solutions to the equation in (0, 2pi) sin(6x)+sin(2x)=0

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how do i go about solving a trig identity; that simplify s 1-sin^2 theta/1-cos theta

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