Inactive Tutor answered 08/07/25
Use the Pythagorean Theorem or its corollary the distance formula
d = sqr(x^2 +y^2) where x and y are the differences in the x and y values of the two points
d = sqr(49+4) = sqr53
= about 7.28
Inactive Tutor answered 08/07/25
Use the Pythagorean Theorem or its corollary the distance formula
d = sqr(x^2 +y^2) where x and y are the differences in the x and y values of the two points
d = sqr(49+4) = sqr53
= about 7.28
Inactive Tutor answered 04/01/22
You will need to use the distance formula
d = sqrt [ (y2 - y1)2 + (x2 - x1)2 ]
= sqrt [ (10-3)2 + (-10-(-8))2 ]
= sqrt [ 72 +(- 2)2 ]
= sqrt [ 49 + 4]
= sqrt [ 53 ]
= 7.28
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