how many grams of silver chromate are produced from 33.9 g of silver nitrate?

Answer 1

2Ag⁺ + CrO₄^2- ==> Ag₂CrO₄

33.9 g AgNO₃ x 1 mol AgNO₃ / 170 g = 0.199 mols

mols Ag₂CrO₄ = 0.199 mol AgNO₃ x 1 mol Ag₂CrO₄ / 2 mol AgNO₃ = 0.0997 mols

mass Ag₂CrO₄ = 0.0997 mols x 331 g / mol = 33.0 g Ag₂CrO₄