J.R. S. answered • 03/30/22
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1). 6.025 g x 0.0025% = 0.0001506 g x 1000 mg / g = 0.1506 mg
2). 6.025 g sample x 0.0025 g Fe / 100 g sample = 0.0001506 g x 1000 mg / g = 0.1506 mg
Madelyn B.
What volume of the Sample Stock Solution (from Question 2) is needed to prepare 25.0 mL of a Dilute Sample Solution with a concentration of 0.30 ppm Fe?
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If all of the iron from Question 1 is diluted in a 50-mL flask (Sample Stock Solution), what is the concentration, in ppm, of the resulting solution?04/03/22