Sa M.
asked • 03/29/22Find the value of Ksp
Determine the value of Ksp for Mg(CN)2 by constructing an ICE table. The molar solubility of Mg(CN)2 is 1.4x10^-5 M at certain temperature.
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1 Expert Answer
J.R. S. answered • 03/29/22
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You are absolutely correct, but you really don't need "x" in the ICE table since you already know the molar solubility. Maybe just a matter of "semantics" or nomenclature, or approach. But the bottom line is you did it correctly.
Mg(CN)2(s) <==> Mg2+(aq) + 2CN-(aq)
.....................................0................0...............I
.............................+1.4x10-5......+2.8x10-5....C
..............................+1.4x10-5......+2.8x10-5....E
Ksp = [Mg2+][CN-]2 = (1.4x10-5)(2.8x10-5)2
Ksp = 1.1x10-14
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Sa M.
would the change in concentration (in the ICE table) would be 1.4x10^-5 or it would be x for Mg2+, and 2x for CN-? Because in the ICE table I put in the change in concentration x for Mg, and 2x for CN-. Then under the equilibrium in concentration I put 1.4x10^-5 for Mg2+, and 2.8x10^-5 for CN-. But the app told me that "the change in concentration for Mg2+ and CN- is known, so I should be able to determine a number to represent the amount"03/29/22