Ember B.

asked • 03/28/22

If 402 mol of octane combusts, what volume of carbon dioxcideis produced at 12.0 degrees celcius aand 0.995 atm

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 402 mol of octane combusts, what volume of carbon dioxide is produced at 12.0 ∘C and 0.995 atm?

Stanton D.

So Ember B., Just carry the # mol for the octane through the proportions of the balanced equation. You know how to work those coefficients, right? That will give you 8*402 mol of CO2. Use your Universal Gas Law to figure that at the specified conditions (the CO2 isn't "produced" at those conditions; this standard text means that you take it and set it to those conditions by appropriate manipulations of temperature and pressure). Curious coincidence, You and Octane meeting -- combustion was .... inevitable? -- Cheers, --Mr. d.
Report

03/29/22

1 Expert Answer

By:

J.R. S. answered • 03/29/22

Tutor
5.0 (145)

Ph.D. University Professor with 10+ years Tutoring Experience
About this tutor ›
About this tutor ›

2C8H18(l) + 25O2(g) ==> 16CO2(g) + 18H2O(l) ... balanced equation

402 mol C8H18 x 16 mol CO2 / 2 mol C8H18 = 3216 mols CO produced


Now we use the ideal gas law to convert 3216 mols CO2 to volume (in liters)

PV= nRT

P = pressure = 0.995 atm

V = volume in liters = ?

n = moles = 3216

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 12.0º + 273 = 285K

Solving for V, we have...

V = nRT/P = (3216)(0.0821)(285) / 0.995

V = 75,600 L (3 sig. figs)

Upvote • 0 Downvote
More
Report

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.