How much heat is released when 17.9 g of Al react with excess Fe2O3 ? Show the conversions required to solve this problem

Question

How much heat is released when 17.9 g of Al react with excess Fe₂O₃ ? Show the conversions required to solve this problem

2 Al(s)+Fe₂O₃(s)⟶Al₂O₃(s)+2 Fe(s) Δ𝐻=−852 kJ

17.9 g Al * (-------) *(-------) = ______g

Answer Bank

1 mol Al 55.85 g Fe 101.96 g Al₂O₃

159.70 g Fe₂O₃ -852kJ 2 mol Al 2 mol Fe

1 mol Fe₂O₃ 26.98 g Al 1 mol Al₂ O₃

Answer 1

2 Al(s) + Fe₂O₃(s )==> Al₂O₃(s) + 2 Fe(s) ... Δ𝐻=−852 kJ

17.9 g Al x 1 mol Al / 55.85 g x -852 kJ / 2 mol Al = -137 kJ (not g) The answer will be in kJ, not in g