J.R. S. answered 03/27/22
Ph.D. University Professor with 10+ years Tutoring Experience
Iron(III) nitrate = Fe(NO3)3
Sodium sulfate = Na2SO4
Molecular
2Fe(NO3)3(aq) + 3Na2SO4(aq) -> Fe2(SO4)3(s) + 6NaNO3(aq)
Total ionic and complete ionic are the same.
2Fe3+(aq) + 6NO3(aq) + 6Na+(aq) + 3SO42-(aq) -> Fe2(SO4)3(s) + 6Na+(aq) + 6NO3(aq)
net ionic
2Fe3+(aq) + 3SO42-(aq) -> Fe2(SO4)3(s)