What is the Ksp of BaF2?

Question

Suppose a saturated solution of barium fluoride contains 1.48 * 10^-2 M F-. What is the Ksp of BaF2?

Answer 1

BaF2 —> Ba²⁺ + 2F-

if F = 1.48x10^-2 then Ba = 1/2 that or 7.4x10^-3

Ksp = [Ba][F]²

Ksp =(7.4x10^-3)(1.48x10^-2)²

solve for Ksp = 1.62x10^-6