J.R. S. answered 03/26/22
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SO2 + 2H2S ==> 2H2O + 3S ... balanced equation
oxidation number of S in H2S on the left is 2-
oxidation number of S in SO2 on the left is 4+
oxidation number of S on the right is zero
So, H2S has acted as a reducing agent (option b)
0825 2.
thanks!03/28/22