A 0.16 M solution of a base is 2.4% hydrolyzed (𝛼=0.024). Find 𝐾b. 𝐾b=

Answer 1

Let B represent the base.

B + H₂O ==> BH⁺ + OH^-

If initial B = 0.16 M and 2.4% is hydrolyzed, then [BH⁺] = [OH^-] = 0.026 x 0.16 M = 0.00384 M

Kb = [BH⁺][OH^-] / [B] = (0.00384)(0.00384) / 0.16

Kb = 9.2x10^-5