J.R. S. answered 03/22/22
Ph.D. University Professor with 10+ years Tutoring Experience
Henderson Hasselbalch equation: pH = pKa + log [conj.base] / [acid]
pKa = -log Ka = -log 1.8x10-5 = 4.74
Buffer A:
4.00 = 4.74 + log [acetate]/[acetic acid]
log [acetate]/[acetic acid] = -0.74
[acetate]/[acetic acid] = 0.182
x/0.1 = 0.182
x = [acetate] = 0.0182 M
0.0182 mol/L x 0.050 L x 136.08 g / mol = 0.124 g sodium acetate, trihydrate
Since the molarity of the acetic acid is given to only 1 sig. fig. you might want to report the answer as 0.1 g
Buffer B:
Same as buffer A