How many milliliters of water must be added to 265 mL of a one. 75 M HCL solution to dilute it to 750 M assuming volumes are additive

Answer 1

I'll assume you meant to write "how many mls of water must be added to 265 ml of 1.75 M HCl to dilute it to 0.750 M?

V1M1 = V2M2

V1 = initial volume = 265 m

M1 = initial molarity = 1.75 M

V2 = final volume = ?

M2 = final molarity = 0.75 M

(265 ml)(1.75 M) = (V2)(0.75 M)

V2 = 618 mls

Volume of water needed = 618 ml - 265 ml = 353 mls of water need to be added