A solution contains 22.9 g of Al+3 ion. How many equivalents of Al+3 ion are in the solution

Answer 1

atomic mass Al = 26.98 g/mol

moles Al³⁺ = 22.9 g x 1 mol / 26.98 = 0.849 moles Al³⁺

Each mole of Al³⁺ has 3 equivalents, so total number of equivalents of Al³⁺ ion is solution is ...

0.849 mols x 3 equiv / mol = 2.55 equivalents of Al³⁺