If chlorine gas is bubbled through potassium iodide solution, iodine is produced. The unbalanced equation is:

Question

Calculate the mass of I2 produced when 6.19x10^4 g of chlorine gas is bubbled through an excess amount of potassium iodide solution.

Hints: Balance Equation. Get molar mass of CI2. Get mole ratio between CI2 and I2. Get molar mass of I2.

please explain me how to solve this.

Answer 1

First, write the correctly balanced equation for this reaction:

2KCl + Cl₂ ==> 2KCl + I₂

molar mass Cl2 = 70.9 g/mol

molar mass I2 = 254 g/mol

The steps in doing this problem are ...

1). find the moles of Cl₂ gas used using the molar mass of Cl₂

2). find the moles of I₂ produced from that many moles of Cl₂ using the balanced equation

3). convert moles of I₂ to grams of I₂ using the molar mass of I₂

1). moles Cl₂ = 6.19x10⁴ g Cl₂ x 1 mol Cl₂ / 70.9 g = 873 moles Cl₂

2). moles I₂ produced = 873 mols Cl₂ x 1 mol I₂ / mol Cl₂ = 873 moles I₂ produced

3). mass I₂ = 873 mols I₂ x 254 g I₂ / mol = 221,742 g I₂ = 2.22x10⁵ g I₂