J.R. S. answered 03/21/22
Ph.D. University Professor with 10+ years Tutoring Experience
2Mg(s) + O2(g) ==> 2MgO(s) ... balanced equation
1 mol of any ideal gas at STP = 22.4 L
14.4 L O2 x 1 mol O2 / 22.4 L = 0.643 mols O2
0.643 mols O2 x 2 mol MgO / mol O2 = 1.29 mols MgO
1.29 mols MgO x 40.3 g MgO/ mol = 51.8 g MgO