What is the remaining percent of container A

Question

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 18 feet and a height of 16 feet. Container B has a diameter of 12 feet and a height of 20 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full.

After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot?

Answer 1

Essentially we are looking for the volume of A - volume of B because we have a full container of A losing water equivalent to the volume of container B.

First we need to find each container's volume.

The formula for the volume of a cylinder is V=h*pi*r^2, where h is height and r is the radius.

The height and radius for A is 16 and 9.

V(A)=16*pi*9^2=1296pi.

The height and radius for B is 20 and 6.

V(B)=20*pi*6^2=720pi.

Now we look for the difference between V(A) and V(B).

V(A)-V(B)=1296pi-720pi=576pi.

The questions asks us to round to the nearest tenth of a cubic foot.

576pi equates to about 1809.55736, and to the nearest tenth of a cubic foot, the final answer should be 1809.6 cubic feet.