Temperature and Volume

Question

What Celsius temperature, T₂ is required to change the volume of the gas sample in Part A ( T₁ = 33 degree Celsius, V₁ = 1.22×10³  ) to a volume of 2.44×10³? Assume no change in pressure or the amount of gas in the balloon.

*please explain this step-by-step for me. I do not understand fully

Answer 1

Ashley,

@Rodrigo F. has supplied a correct approach and answer to your question, but I I thought I'd add some explanation, since you stated you don't understand the process.

Since there is no change in pressure, when the volume increases, the temperature must also increase. If the temperature didn't increase, the pressure would go down when you increased the volume. The relationship between T (temperature) and V (volume) is a direct one. So, if temperature increases, the volume must increase to maintain the same pressure. If temperature decreases, volume must decrease to maintain the same pressure. And vice versa.

This is why V1/T1 = V2/T2 works in solving such problems. This is known as Charles Law, in case you want to look it up and read more about it.

Answer 2

You have to use the equation:

V_o/T_o = V₁/T₁ (Remember that the temperature is in K = °C + 273)

1.22*10³ /306 = 2.44*10³/T₁

T₁ = 712 K

T₁ = 712-273

T₁ = 439°C