Molarity/molality help #1

Question

Suppose you wanted to produce 1.22 L of a 3.37 M aqueous solution of H₂SO₄

How many grams of solute are needed to make this solution?

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How many grams of solute are needed to make 2.59 L of a 1.84 M solution of Ba(NO₃)₂?

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Answer 1

molar mass H₂SO₄ = 98.1 g/mol

3.37 M H₂SO₄ = 3.37 moles H₂SO₄ / liter of solution

To make 1.22 L, we need...

3.37 mols / L x 1.22 L = 4.11 mols H₂SO₄

g H₂SO₄ = 4.11 mols x 98.1 g / mol = 403 g H₂SO₄

For the 2nd problem, do it the same way and use molar mass Ba(OH)2 = 171 g / mol