What is the percentage of container b

Question

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 4 feet and a height of 10 feet. Container B has a radius of 3 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

Answer 1

Volume of a cylinder = π r^2 h

Volume of container A = π x 4^2 x 10 = 160 π

Volume of container B = π x 3^2 x 18 = 162 π

Volume of container A < volume of container B; hence all the water from A (160 π ) can be poured into B. A will be empty and B will contain 160 π .

Fraction of B that is full is 160 π / 162 π

Percent fraction of B that is full is (160 π / 162 π ) * 100 = 98.76%

Round to the nearest tenth to get 98.8%

Answer 2

Vol_A = (4)π(10)

Vol_B = (3)π(18)

Vol_% = Vol_A / Vol_B