Raymond B. answered 03/16/22
Math, microeconomics or criminal justice
P(A)= .5
P(B) = .5
A and B are mutually exclusive events
then P(A intersection B) = 0
They'd have P(A intersection B) = 0 regardless what P(A) and P(B) were, if they were mutually exclusive events. IF they're mutually exclusive they can't both happen at the same time.
to calculate P(A or B) = P(A v B) would equal .5 + .5 = 1 Draw a Venn diagram. half the rectangle is A, the other half B. whatever you randomly chose, you'd get A or B.
if you randomly picked A, then a 2nd time randomly picked B from the same universal set, odds of A then B or B then A would be the multiple .5 x. 5 = .25
probability of A twice or B twice would also be .25, similar to getting two heads or two tails on two flips of a coin
But the question was what is the probability of getting both A and B at the same time. That's zero. On a Venn diagram there is no overlap of A and B. The overlap would be where A and B occur at the same time. That's probability = 0