Three people are selected at random. Find the probability that all three are born on Sunday.

Answer 1

(1/7)^3 = 1/343 = about .002915451895 = about 0.29 %

= about 1/3 of 1% chance all 3 are born on Sunday, or all born on all the same day of the week

without major odds don't bet on it

for any one person randomly selected, it's 1/7 chance they were born on Sunday

same with the next person, and the 3rd person

multiply the probabilities together: 1/7 x 1/7 x 1/7 = (1/7)^3 = 1/343 = about 0.29%