Aidan H.

asked • 03/15/22

How do you solve this?

I'm quite stumped on how to solve this. Hopefully a picture in the comments will give you an idea of what's going on... I tried solving this on my own but I got an answer that didn't seem right....



Mark M.

Access is restricted to Kami.
Report

03/15/22

Aidan H.

well shucks.... how do you post a picture to Wyzant?
Report

03/15/22

Aidan H.

Let me describe it: so there's a circle. a gradually slanted tangent is at the top of the circle. Below it, there's an angle measurement of 7x-10 degrees. A secant goes from point E(located at the top of the circle) to point D(located at the bottom of the circle). The measure of arc ED is 120 degrees. Given the information, how does one solve this. I only need the equations, nothing more....
Report

03/15/22

Mark M.

The text book has a formula to determine the lengths of a tangent and a secant from an external point.
Report

03/15/22

Aidan H.

Mark M., I do not have a textbook at my disposal but I'll search it up anyway....
Report

03/15/22

Mark M.

Length of tangent squared is equal to the product of the length of the entire secant and the portion of the secant outside of the circle.
Report

03/16/22

Brenda D.

tutor
Found the comments thanks again!
Report

03/18/22

1 Expert Answer

By:

Jeff U. answered • 03/15/22

Tutor
5.0 (52)

Relatable Math Tutor Specializing in Online Calculus Tutoring

See tutors like this
See tutors like this

Hey Aiden!


I'm not 100% clear on what the diagram looks like, but it sounds like you're working with a circle with a secant and a tangent. What you need to know is that in this situation, the angle created by a secant and a tangent is 1/2 the measure of its intercepted arc. So, based on your description, it sounds like your labeled angle should be 60 degrees. Then you'll just have to solve for x!


Hope that helps.

Upvote • 0 Downvote
More
Report

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.