Raymond B. answered 03/15/22
Math, microeconomics or criminal justice
a + 4b - c without more information doesn't allow for solving the value of any of the letters.
If a+4b -c = 0
then you can solve for each letter, in terms of the other two letters
a= c-4b
c = a+4b
b=(c-a)/4
If you had 3 equations, you could solve for unique numerical values of each letter, unless the equations were linearly dependent, or contradictory.
if a+4b -c = 0
and a 2nd equation were a+4b -c = 1,
then the system of equations has no solution, as they're contradictory
if 3 equations, 3 unknowns were linearly dependent, such as
a+4b -c = 0
2a +8b -2c = 0
3a +12b -3c = 0
are just multiples of each other and that means an infinite number of solutions for a,b and c
if 3 equations, 3 unknowns are linearly independent (not multiples of each other) and not contradictory, then there is a unique (one) solution for a, b and c
such as
a + 4b - c = 0
a+4b = 2
a-c = 4
then
a = 6, b=-1, c=2 is the one and only solution
if you graphed the equations in 3 dimensions, they would intersect at that point (a,b,c) = (6,-1,2)