J.R. S. answered 03/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
At STP, 1 mole of any ideal gas = 22.4 L
First, we'll find the mols of NH3 and then find the moles of N2 and finally the grams of N2.
20 L NH3 x 1 mol NH3 / 22.4 L = 0.893 moles NH3
From the balanced equation, we can now find the moles of N2 needed:
0.893 mols NH3 x 1 mol N2 / 2 mols NH3 = 0.447 mols N2 needed
Now we convert this to grams of N2 using the molar mass of N2 of 28 g/mol:
0.447 mols N2 x 28 g / mol = 12.5 g N2