J.R. S. answered 03/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
2A + 3B→C ... ΔHrxn = −115kJ
Part A: 1 mol A x -115 kJ / 2 mol A = -57.5 kJ
Part B: 7 mol A x -115 kJ / 2 mol A = -403 kJ
Part C: 2 mol B x -115 kJ / 3 mol B = -76.7 kJ
Part D: 9 mol B x -115 kJ / 3 mol B = -345 kJ