A solution has an initial concentration of acid HA of 1.4 M. If the equilibrium hydronium ion concentration is 0.12 M, what is the percent ionization of the acid?

Answer 1

HA <==> H⁺ + A^-

[H⁺] = 0.12 M

% ionization = [H+] / [HA] (x100%) = 0.12 M / 1.4 M (x1005) = 8.6% ionized