How many moles of lithium nitrate will be needed to make 2.45 moles of Pb(NOg)4, assuming that you have an adequate amount of Pb(SO4)2 to do the reaction?

Question

I'm completely lost on this one. Help!

Answer 1

Haylee

First, you MUST always write the correctly balanced equation.

4LiNO₃ + Pb(SO₄)₂ ==> 2Li₂SO₄ + Pb(NO₃)₄ ... balanced equation

Once you have the balanced equation, we use the mole ratio of lithium nitrate (LiNO₃) to Pb(NO₃)₄ and dimensional analysis to get the answer.

2.45 moles Pb(NO₃)₄ x 4 moles LiNO₃ / mole Pb(NO₃)₄ = 9.80 moles LiNO₃

Does this makes sense, Haylee?

Answer 2

The balanced chemical equation for this reaction is

4 LiNO3​ + Pb(SO4​)2 ​→ Pb(NO3​)4 ​+ 2Li2​SO4

meaning that the mole ratio of interest here is 4 mol LiNO3: 1 mol​ Pb(NO3)4

from there then you can convert the given value over using the mole ratio

2.45 moles Pb(NO3)4 x 4 mol LiNO3 / 1 mol Pb(NO3)4 = 9.8 moles LiNO3

so you will need 9.8 moles of lithium nitrate