What volume of 0.861 mol L-1 NaOH solution is needed to just completely neutralize a 0.987 mol L-1 solution of CH3COOH with volume 27 mL? Your answer should be expressed in mL.

Answer 1

Let's look at the balanced equation:

CH3COOH + NaOH ==> H2O + CH3COONa

moles CH3COOH present = 27 mls x 1 L / 1000 mls x 0.987 mol / L = 0.0266 mols CH3COOH

moles NaOH needed = 0.0266 moles NaOH according to the mole ratio in the balanced equation

Volume NaOH = 0.0266 mols x 1 L / 0.861 moles = 0.031 L = 31 ms (2 sig. figs.)