
Philip P. answered 03/07/22
Affordable, Experienced, and Patient Algebra Tutor
In a direct variation, the y values increase as the x values increase. That is not the case here - the y values are going down as the x values get larger, so an inverse variation would be appropriate. Try:
y = k/x
Solving for k:
yx = k
The equation could be y = k/x2 or some other power of x. But if we plug in all three (x,y) combinations and get the same value for k, we know y=k/x is right.
yx = k
(100)(0.5) = 50
(20)(2.5) = 50
(5)(10) = 50
So yep, k = 50 and the equation is y = 50/x.